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Napaka pri avtorski honorarjih in plačah
Rank: PA User
Joined: 14/01/2010(UTC) Posts: 1
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Pozdravljeni.
Vsakič ko želim potrditi listo za oddajo avtorskih honorarjev (včasih tudi od plač) v Pantheonu mi javi napako in moram na silo zapreti celoten program, da sploh lahko kam pridem. Včasih je pomagalo, da se je datume napisalo ročno (ne da bi s klikanjem izbrali), vendar sedaj tudi to več ne deluje. Vprilogi vam pošiljam napako shranjeno v txt datoteko. To se dogaja že nekaj zadnjih nadgradenj in je vsakič slabše.
Lep pozdrav, Gaj Lukic
TXT:
date/time : 2010-04-08, 09:07:42, 653ms computer name : MARINA user name : marinag <admin> operating system : Windows XP Service Pack 3 build 2600 system language : Slovenian system up time : 1 hour 1 minute program up time : 8 minutes 4 seconds processors : 2x Pentium(R) Dual-Core CPU E5200 @ 2.50GHz physical memory : 1397/2038 MB (free/total) free disk space : (C:) 194,39 GB display mode : 1280x1024, 32 bit process id : $9d8 allocated memory : 220,18 MB executable : Pantheon55_SQL.exe exec. date/time : 2010-02-10 15:30 version : 5.5.45.20 compiled with : BCB 2006 madExcept version : 3.0d callstack crc : $2cd4e5ce, $1063cc0e, $1063cc0e exception number : 17 exception class : EMSError exception message : Invalid object name 'tHR_LinkPayFgnTransSlry'.
Main ($ee0): 008931ba +462 Pantheon55_SQL.exe OLEDBAccess TOLEDBConnection.OLEDBError 00892d0a +01a Pantheon55_SQL.exe OLEDBAccess TOLEDBConnection.Check 008956a9 +039 Pantheon55_SQL.exe OLEDBAccess TOLEDBCommand.Check 008983f4 +19c Pantheon55_SQL.exe OLEDBAccess OpenOrExec 008984d8 +050 Pantheon55_SQL.exe OLEDBAccess DoExecute 008986da +04a Pantheon55_SQL.exe OLEDBAccess TOLEDBCommand.Execute 0088660c +058 Pantheon55_SQL.exe DBAccess TCustomDASQL.InternalExecute 008bc4fd +005 Pantheon55_SQL.exe MSAccess TMSSQL.InternalExecute 0088674b +0b3 Pantheon55_SQL.exe DBAccess TCustomDASQL.Execute 008bcfea +052 Pantheon55_SQL.exe MSAccess TMSSQL.Execute 0088668f +007 Pantheon55_SQL.exe DBAccess TCustomDASQL.Execute 0088b040 +04c Pantheon55_SQL.exe DBAccess TDBAccessUtils.Execute 0087e588 +124 Pantheon55_SQL.exe DBAccess TCustomDADataSet.UpdateExecute 008b98f2 +0ee Pantheon55_SQL.exe MSAccess TCustomMSDataSet.UpdateExecute 0088033f +1f7 Pantheon55_SQL.exe DBAccess TCustomDADataSet.PerformSQL 008b9dae +022 Pantheon55_SQL.exe MSAccess TCustomMSDataSet.PerformSQL 009ad6d6 +03e Pantheon55_SQL.exe dlDatabase 5218 +9 TdlDataset.PerformSQL 0087d6fc +00c Pantheon55_SQL.exe DBAccess TCustomDADataSet.PerformDelete 0086d82d +035 Pantheon55_SQL.exe MemDS TMemDataSet.DoPerformDelete 0085fcfd +00d Pantheon55_SQL.exe MemData TData.InternalDelete 0089c57b +00f Pantheon55_SQL.exe OLEDBAccess TOLEDBRecordSet.InternalDelete 00864af7 +027 Pantheon55_SQL.exe MemData TMemData.DeleteRecord 0089bb0d +085 Pantheon55_SQL.exe OLEDBAccess TOLEDBRecordSet.DeleteRecord 0086d254 +050 Pantheon55_SQL.exe MemDS TMemDataSet.InternalDelete 004b1589 +029 Pantheon55_SQL.exe DB 10834 +5 TDataSet.CheckOperation 004b128d +0a1 Pantheon55_SQL.exe DB 10743 +8 TDataSet.Delete 00ba28c1 +219 Pantheon55_SQL.exe Navigator3 1375 +44 TNavigator3.BtnClick 00ba1b53 +037 Pantheon55_SQL.exe Navigator3 1142 +4 TNavigator3.ClickHandler 0050a2f4 +064 Pantheon55_SQL.exe Controls TControl.Click 008311b3 +087 Pantheon55_SQL.exe dlcxButton 872 +16 TdlCustomButton.Click 0050a76f +06b Pantheon55_SQL.exe Controls TControl.WMLButtonUp 00509def +2bb Pantheon55_SQL.exe Controls TControl.WndProc 0050df03 +4fb Pantheon55_SQL.exe Controls TWinControl.WndProc 005bc455 +119 Pantheon55_SQL.exe cxControls 2615 +17 TcxControl.WndProc 0050d62c +02c Pantheon55_SQL.exe Controls TWinControl.MainWndProc 00487850 +014 Pantheon55_SQL.exe Classes StdWndProc 7e4196c2 +00a USER32.dll DispatchMessageA 004f70a8 +0fc Pantheon55_SQL.exe Forms TApplication.ProcessMessage 004f70e2 +00a Pantheon55_SQL.exe Forms TApplication.HandleMessage 004f73d7 +0b3 Pantheon55_SQL.exe Forms TApplication.Run 0266c91b +10f Pantheon55_SQL.exe Pantheon55 1124 +34 initialization
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Rank: Datalab
Joined: 23/02/2010(UTC) Posts: 8
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Pozdravljen!
Poskusite s ponovno nadgradnjo. V kolikor pa še vedno ne bo delovalo, preverite na bazi, če obstaja tabela dbo.tHR_LinkPayFgnTransSlry. Če je ni, poženite spodnjo skripto:
create table dbo.tHR_LinkPayFgnTransSlry ( acKey char(13) NOT NULL DEFAULT (''), anNo int NOT NULL DEFAULT (0), acLnkKey char(13) NOT NULL DEFAULT (''), anLnkNo int NOT NULL DEFAULT (0), acType char(2) NOT NULL DEFAULT (''), acTypeA char(2) NULL DEFAULT (''), acTypeB char(3) NULL DEFAULT (''), anFieldNA float NOT NULL DEFAULT (0), anFieldNB float NOT NULL DEFAULT (0), anUserId int NULL DEFAULT (0), adDate datetime NULL CHECK ([adDate]=dateadd(day,datediff(day,(0),[adDate]),(0))), acValue varchar(35) NULL DEFAULT (''), anUserChg int NULL DEFAULT (0), adTimeIns datetime NULL DEFAULT (getdate()), adTimeChg datetime NULL DEFAULT (getdate()), anUserIns int NULL DEFAULT (0)); ALTER TABLE DBO.tHR_LinkPayFgnTransSlry ADD CONSTRAINT kHR_LinkPayFgnTransSlry_0 PRIMARY KEY (acKey,anNo,acLnkKey,anLnkNo,acType); CREATE INDEX iHR_LinkPayFgnTransSlry_L1 ON DBO.tHR_LinkPayFgnTransSlry(acLnkKey,anLnkNo,acType); ALTER TABLE dbo.tHR_LinkPayFgnTransSlry ADD CONSTRAINT rtHR_LinkPayFgnTransSlry_tHE_PayFgnTrans_1 FOREIGN KEY(acKey) REFERENCES dbo.tHE_PayFgnTrans(acKey); ALTER TABLE dbo.tHR_LinkPayFgnTransSlry ADD CONSTRAINT rtHR_LinkPayFgnTransSlry_tHR_SlryPrep_2 FOREIGN KEY(acLnkKey) REFERENCES dbo.tHR_SlryPrep(acKey);
Lep pozdrav, Tina
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