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          Using logical operator without logical expression
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The second character of #xx# must be a transaction type (D, K, S, P, or O)!

The second character of #xx# must be a transaction type (D, K, S, P, or O)!

The second character of #xx# must be a transaction type (D, K, S, P or O)!

 
Performing formula testing in posting template checks for correct syntax and whether the operand between the hashes is valid.

Posting template formulas must be formatted as follows:

First character Second character Followed by

R - Revaluation

S - Sum

O - Interest

D – debit transactions in a given period

K – credit transactions in a given period

S – balance in given period= |D - K|

P - credit – debit (credit balance in given period) = K - D

O – debit – credit (debit balance in given period) = D - K

If the second character of the expression is not one of the five listed above, an error is returned.

 any expression for referring to one or more accounts, e.g.:

11%

The operand that failed the validation is shown in the error message. Focus is shifted to the record in question.

37005.png

Clicking OK, the cursor shifts to the place in the formula where the error occurred.

Solution:

Enter a valid transaction type.

Examples:

Correct Incorrect
#OO11%# #O11%#
#SD11%# #D11%#
#RD11%# #RDD11%#

 
 

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