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          Using logical operator without logical expression
          Opening or closing round bracket missing!
          Opening or closing square bracket missing!
          Last character of the formula is an operator!
          Adjacent hashes!
          Syntax error in conditional statement. Correct syntax is [condition:value]
          Adjacent operators (xx)!
          Variable not enclosed in hashes (#)!
          Illegal characters: xyz
          Unknown error!
          The first character of #xx# must be a transaction type or a column mark!
          The line number must be an integer (#xx#)!
          The first character of #xx# must be an operation type (R, S, O or A)!
          The second character of #xx# must be a transaction type (D, K, S, P, or O)!
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Illegal Characters

The constants in the formulas are entered as arbitrary real numbers, and the mathematical and logical operations are performed using the allowed operators. Any character that is not explicitly allowed is therefore illegal.

HINT

For a list of allowed characters, see chapter Formulas.

 

The formula test expects that only allowed characters are used in a formula. If this condition is not met, the formula test returns an error:

33034.jpg

Characters that are used in the formula but are not allowed are also displayed. Formula testing puts us on the problematic character, to make it easier to correct the formula. (If there are more than one such characters in a formula, it puts us on the first illegal character found.)

There are two possible solutions:

1. Deleting an illegal character if it is entered accidentally.

2. Correcting the entered formula accordingly, using the allowed characters.

Correct Incorrect
To Example 1:

#QUANTITY# *75

 *75!
To Example 2:

*75/100

#QUANTITY# *0.75

#QUANTITY# *0.75

PRICE*1,2

*75%

#QUANTITY# x 0,75

QUANTITY *0,75

#PRICE#*1,2

 

RELATED TOPICS:

Using logical operator without logical expression

Adjacent hashes!

 
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